Find the velocity of the wind relative to the boat

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Homework Help Overview

The problem involves determining the velocity of the wind relative to a boat during a race, with specific velocities and directions provided. The subject area includes vector analysis and relative motion in physics.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the vector representation of velocities and question the definitions of the coordinate directions used (i and j). There is an exploration of the apparent wind direction from the boat's perspective and the implications of sign conventions in vector calculations.

Discussion Status

The discussion is ongoing, with participants providing feedback on the original poster's reasoning and questioning the clarity of terms used. Some participants express agreement with the calculations, while others highlight potential confusion in the interpretation of direction and vector components.

Contextual Notes

There is mention of a book's answer that differs from the calculations presented, indicating a possible discrepancy in understanding or interpretation of the problem setup. Participants are also addressing the importance of consistent terminology in vector analysis.

gnits
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Homework Statement
Find velocity of wind relative to boat
Relevant Equations
Va-Vb=Vab
Could someone please help me see where I am going wrong here?

During a race between two boats A and B there is a wind of 18 km/h blowing from due north. The resultant velocity if A is 12 km/h on a bearing of 060. Find the direction of the wind relative to A.

My reasoning:

(Relative to the Earth) A is traveling on a vector ##12\,sin(60) i +12\,cos(60) j = 6\sqrt{3}i + 6j##

(Relative to the Earth) The wind is traveling on a vector ##-18j##

So from A's point of view, vertically, the wind will seem to be coming in a direction of ##-18-6=-24i## and horizontally from a direction of ##0-6\sqrt{3}i=-6\sqrt{3}i##

And so from A's point of view the wind will be coming from a direction of ##270 - tan^{-1}(-24\,/\,(6\sqrt{3}))=270-66.59=203.41##

Book's answer is 193.9.

Thanks for any help,
Mitch.
 
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Which directions are ##i## and ##j## relative to North?
 
i is North and j is East
 
gnits said:
i is North and j is East
Unless I'm missing something, your answer looks correct. Although, with ##i## being East. You seem to have ##i## changing between East and North from one line to the next.

Why not use E and N for East and North?
 
gnits said:
So from A's point of view, vertically, the wind will seem to be coming in a direction of −18−6=−24i−18−6=−24i-18-6=-24i and horizontally from a direction of 0−6√3i=−6√3i0−63i=−63i0-6\sqrt{3}i=-6\sqrt{3}i

I think there is much confusion and imprecision in this statement. First, does “coming in a direction” mean “coming from a direction” or “blowing in a direction”? Those are opposite things. You’ve mixed them. Which do you mean? You use -18. With the negative sign that suggests you mean the direction the wind is traveling toward, not the direction it is coming from. (Also note that you used “i” where you meant “j”.) To this you add -6. This suggests that you believe that the apparent wind is opposite the direction of travel of the boat. (correct). Ok, if you meant the direction the wind is traveling toward, and you meant to use a j instead of an i, so far so good. However in the horizontal part directly below you say “the wind is coming from” but then use the negative sign indicating that you think the apparent wind is in the same direction as the boat travels (incorrect). So, which is it? I know it may sound like I’m nit picking, but this stuff is important. You will confuse yourself.
 
203.41 degrees looks good using cosine rule for Va , then sine rule for bearing of wind relative to boat.
 
Thanks everybody for your help, I really appreciate it, it was very helpful.

Mitch.
 

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