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gnits
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- Homework Statement
- Find velocity of wind relative to boat
- Relevant Equations
- Va-Vb=Vab
Could someone please help me see where I am going wrong here?
During a race between two boats A and B there is a wind of 18 km/h blowing from due north. The resultant velocity if A is 12 km/h on a bearing of 060. Find the direction of the wind relative to A.
My reasoning:
(Relative to the Earth) A is traveling on a vector ##12\,sin(60) i +12\,cos(60) j = 6\sqrt{3}i + 6j##
(Relative to the Earth) The wind is traveling on a vector ##-18j##
So from A's point of view, vertically, the wind will seem to be coming in a direction of ##-18-6=-24i## and horizontally from a direction of ##0-6\sqrt{3}i=-6\sqrt{3}i##
And so from A's point of view the wind will be coming from a direction of ##270 - tan^{-1}(-24\,/\,(6\sqrt{3}))=270-66.59=203.41##
Book's answer is 193.9.
Thanks for any help,
Mitch.
During a race between two boats A and B there is a wind of 18 km/h blowing from due north. The resultant velocity if A is 12 km/h on a bearing of 060. Find the direction of the wind relative to A.
My reasoning:
(Relative to the Earth) A is traveling on a vector ##12\,sin(60) i +12\,cos(60) j = 6\sqrt{3}i + 6j##
(Relative to the Earth) The wind is traveling on a vector ##-18j##
So from A's point of view, vertically, the wind will seem to be coming in a direction of ##-18-6=-24i## and horizontally from a direction of ##0-6\sqrt{3}i=-6\sqrt{3}i##
And so from A's point of view the wind will be coming from a direction of ##270 - tan^{-1}(-24\,/\,(6\sqrt{3}))=270-66.59=203.41##
Book's answer is 193.9.
Thanks for any help,
Mitch.