1. The problem statement, all variables and given/known data An aircraft flew due east fro P to Q at u1 km/h.Wind speed from south west was v km/h.On the return journey from Q to P,due west, the aircraft's speed was u2 km/h, the wind velocity being unchanged.If the speed of the aircraft in still air was x km/h, x>v,show by resolving the perpendicular to PQ.or otherwise,that u1 - u2 = v√2 2. Relevant equations 3. The attempt at a solution[/b/ Can somebody help me with this?I think I made a simple mistake. vpw = (xcosa)i - (xsina)j vw = (v√2/2)i + (v√2/2)j vp = (xcosa + v√2/2)i +(xsina + v√2/2) since the j component must be zero sina = 2v/2x ............. cosa =√(4x^2 -2v^2)/2x vp =x√(4x^2 -2v^2)/2x + v√2/2 = (v√2 + √(4x^2 -2v^2))/2 = u1 return journey since the plane is travelling in the opposite direction vpw = (-xcosa)i - (xsina)j vp = (-xcosa + v√2/2)i +(-xsina + v√2/2)j since j is zero cosa =√(4x^2-2v^2)/2x u2=vp= (v√2 - √4x^2 -2v^2)/2 i u1 - u2 = (√(4x^2 - 2v^2) +√(2v^2))/2 - (√(4x^2 -2v^2) - √(2v^2))/2 If I simplify it doesn't work out.Should I have multiplied u2 by minus 1 since its going in the minus i direction?