Relativistic energy and momentum in particle collisions

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
2 replies · 4K views
swe91
Messages
2
Reaction score
0

Homework Statement


Two particle P and Q each of restmass m0 and moving in collision course at 2/3c in the laboratory frame of reference.
In the same collision but in particle P's frame of reference, P is at rest.

Homework Equations


As the total energy of the particles depends on the frame of reference, do the observers in each frame of reference agree on the number of particles and photons formed in the collision?

The Attempt at a Solution


From
E=[tex]\gamma[/tex]m0c2
p=[tex]\gamma[/tex]m0v
where v=v' from relativistic velocity addition.
and
E2=p2c2+m02c4
I can conclude that the total energy and momentum of the the collision differs. Furthermore, as I do not se how the available energy for particle formation can be the same when the total energy is different, I would conclude that the number of particles would differ depending on the reference frame. However, this does not feel right. As the collision takes place at a "single point" in space, wouldn't it be measured the same from all inertial frames of reference?

Thanks in advance
 
Physics news on Phys.org
Hmmm... Well it is true that momentum and energy change between different frames. People use the invariant rest mass to solve problems like this. But "number" of particles shouldn't be affected by relativity. The energy of the final products may be different but the total number of products won't change.
 
Okey thank you for your answer.
Is this the equation you are referring to?
E = p^2 c^2 + m^2 c^4
So if one uses " the invariant rest mass" does it imply the center of mass frame of reference of one of the particles?
If that is the case, does that imply that the energy of the particles created is equal to the invariant rest mass plus the "minimal amount" of momentum and kinetic energy of the two particles colliding at all times? and that the additional energy from other frames of reference is only kinetic?

In summary: the minimal amount of energy is used to create particles with largest possible mass, hence, at rest. Furthermore, all other energy from other frames of reference is observed as kinetic from respective frame of reference.