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I am working through a QFT book and it gives the relativistic Lagrangian for a free particle as L = -mc^{2}/γ. This doesn't seem consistent with the classical equation L = T - V as it gives a negative kinetic energy ? If L = T - V doesn't apply relativistically then why does the Hamiltonian H = T + V as the total energy still apply ? Thanks

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# Relativistic Lagrangian and Hamiltonian for a free particle

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