High School Relativistic Mass-Energy: Charge & Particles

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The presence of charge contributes to relativistic mass-energy due to the associated electromagnetic field, which has stress-energy. It is not necessary for two particles to attract or repel each other to generate charge-related mass-energy. The Reissner–Nordström metric illustrates how charged black holes exhibit different gravitational properties compared to uncharged ones, with a significant portion of their 'mass' attributed to charge. When charge is removed, the black hole's mass reduces to its irreducible mass, resulting in a distinct change in the gravitational field. Overall, charge plays a crucial role in the mass-energy dynamics of charged particles and black holes.
1977ub
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Does The Presence of Charge Add To Relativistic Mass-Energy, or does it take two particles attracting or repelling one another to generate charge-related mass-energy?
 
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1977ub said:
Does The Presence of Charge Add To Relativistic Mass-Energy,

Yes. The presence of charge means there is an electromagnetic field, and the electromagnetic field has stress-energy.

1977ub said:
does it take two particles attracting or repelling one another to generate charge-related mass-energy?

No.
 
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1977ub said:
Does The Presence of Charge Add To Relativistic Mass-Energy, or does it take two particles attracting or repelling one another to generate charge-related mass-energy?

While PeterDonis has answered the question, you can see this at work in the Reissner–Nordström metric which is the vacuum solution for a charged black hole. Gravity for a charged black hole is-

a_g=\frac{M}{r^2\sqrt{1-\frac{2M}{r}-\frac{Q^2}{r^2}}}

where M=Gm/c^2 (mass in geometric units) and Q=C\sqrt(Gk_e)/c^2 (charge in geometric units) where G is the gravitational constant, c is the speed of light, C is the charge in Coulombs and k_e is Coulomb's constant (as a rule, M\geq Q). Multiply the answer by c^2 for S.I. units of gravity (m/s2).

If charge is removed and the black hole is reduced to it's irreducible mass (the same black hole becoming a Schwarzschild black hole) where-

M_{\text{ir}}=\frac{r_+}{2}\ \ \rightarrow\ \ M=\frac{Q^2}{4M_{\text{ir}}}+M_{\text{ir}}

where M_{\text{ir}} is the irreducible mass and r_+=M+\sqrt{M^2-Q^2} is the outer event horizon, the equation for gravity becomes-

a_g=\frac{M{\text{ir}}}{r^2\sqrt{1-\frac{2M{\text{ir}}}{r}}}

you'll notice a distinct drop in the gravity field at a specific r some distance from the black hole. It might also be worth looking at Kerr-Newman metric which also includes for spin. Up to 50% of RN black hole's 'mass' can be attributed to charge though charged black holes are not considered realistic.

More info-
https://www.physicsforums.com/threads/what-is-irreducible-mass.762993/
 
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In an inertial frame of reference (IFR), there are two fixed points, A and B, which share an entangled state $$ \frac{1}{\sqrt{2}}(|0>_A|1>_B+|1>_A|0>_B) $$ At point A, a measurement is made. The state then collapses to $$ |a>_A|b>_B, \{a,b\}=\{0,1\} $$ We assume that A has the state ##|a>_A## and B has ##|b>_B## simultaneously, i.e., when their synchronized clocks both read time T However, in other inertial frames, due to the relativity of simultaneity, the moment when B has ##|b>_B##...

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