Relativistic Momentum of a particle

Click For Summary
SUMMARY

The discussion focuses on calculating the unknown mass M of a particle that decays into two particles with known masses (m1 = 0.5 GeV/c² and m2 = 1.0 GeV/c²) and measured momenta (p1 = 2.0 GeV/c along the y-axis and p2 = 1.5 GeV/c along the x-axis). The solution involves applying the principles of conservation of momentum and energy to determine both the unknown mass and its speed. The relevant equation for momentum is p = 1/sqrt(1-v²/c²)(mu), which is crucial for solving the problem.

PREREQUISITES
  • Understanding of relativistic momentum and energy conservation principles
  • Familiarity with the concept of particle decay in physics
  • Knowledge of the Pythagorean theorem as it applies to vector addition
  • Basic understanding of mass-energy equivalence (E=mc²)
NEXT STEPS
  • Study the application of conservation laws in particle physics
  • Learn how to calculate relativistic momentum using the formula p = mv/sqrt(1-v²/c²)
  • Explore examples of particle decay reactions and their energy-momentum relationships
  • Investigate the implications of mass-energy equivalence in high-energy physics
USEFUL FOR

This discussion is beneficial for physics students, particle physicists, and anyone interested in understanding relativistic effects in particle decay and collision scenarios.

~Sam~
Messages
70
Reaction score
0

Homework Statement


A particle of unknown mass M decays into two particles of known masses m1 = 0.5 GeV/c2 and m2 = 1.0 GeV/c2, whose momenta are measured to be p1 = 2.0 GeV/c along the positive y-axis and p2 = 1.5 GeV/c along the positive x-axis. Find the unknown mass M and its speed.


Homework Equations



p=1/sqrt(1-v^2/c^2)(mu)

The Attempt at a Solution



I tried summing the momentas, via pythagoras theorem. after that I'm not sure.
 
Physics news on Phys.org
What's the general principle which governs how you can find the answer? I.e. for a given mass 'M,' why wouldn't m1 = 500000 GeV and m2 = 100000 Gev?

Hint: what if you think about the decay reaction as a collision?
 
Ahh I got it...using conservation of energy.
 
use conservation of momentum and energy to get the velocity in ground frame
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 23 ·
Replies
23
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
3
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
5K