Relativistic Rocket: Find Δv in Earth Frame

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SUMMARY

The discussion focuses on applying the relativistic velocity addition formula to calculate the change in velocity (Δv) of a rocket accelerating at 9.81 m/s² from the Earth's frame of reference. The formula used is v = u + v' / sqrt(1 + v'u/c², where v' represents the rocket's instantaneous speed in its own frame. The user attempts to derive Δv using Δv = 9.81*Δt/sqrt(1 + 9.81*Δt/c², but is advised to clarify the variables involved in the formula for accurate application.

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  • Understanding of relativistic physics concepts
  • Familiarity with the relativistic velocity addition formula
  • Knowledge of proper time intervals in physics
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Hebrew21
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Homework Statement


I a little lost on how to use the relativistic velocity addition formula to determine the increase in speed "v" over a short time interval in the Earths frame of reference, for a rocket having left Earth at rest and traveling through space accelerating at constant acc. of 9.81 m/s^2. In the rockets instantaneous frame of reference, the increase in speed is (9.81m/s^2)*Δt where Δt is the proper time interval. The equation must be modified to determine a speed increase Δv over a short interval of time from the Earth frame of reference. I guess the question I have is if I can use this formula to solve for the change in velocity over a small interval of time, for a different reference frame?

Homework Equations



v=u+v'/ sqrt(1+v'u/c^2)

The Attempt at a Solution


Here's what I have so far, not sure if its close:

Δv=9.81*Δt/sqrt(1+9.81*Δt/c^2)
 
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You should review the velocity-addition formula. Identify what v, u, and v' stand for as it relates to this particular problem, and then try again.
 

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