Relativity - Length Contraction

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SUMMARY

The discussion focuses on the concept of length contraction in the context of special relativity, specifically involving a spaceship traveling at 0.75c. Observers on a space station measure the contracted length of the spaceship to be 0.30 km. The calculation provided uses the formula d = d0/γ, where d0 is the proper length and γ is the Lorentz factor. The final calculated length when the spaceship docks is approximately 453.557 meters, confirming the principles of relativity.

PREREQUISITES
  • Understanding of special relativity principles
  • Familiarity with the Lorentz factor (γ)
  • Knowledge of length contraction formula (d = d0/γ)
  • Basic algebra for solving equations
NEXT STEPS
  • Study the derivation of the Lorentz factor (γ) in special relativity
  • Explore examples of length contraction at various speeds
  • Learn about time dilation and its relationship with length contraction
  • Investigate practical applications of relativity in modern physics
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Students of physics, educators teaching special relativity, and anyone interested in understanding the implications of high-speed travel on physical measurements.

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Homework Statement


A spaceship flies past a space station at 0.75c. Observers on the station measure the length of the ship to be 0.30 km. If the ship later docks alongside the station and its length is measured, what would this measured value be?


Homework Equations



d=d0/[tex]\gamma[/tex]

The Attempt at a Solution


d0=300/[tex]\sqrt{1-.75<sup>2</sup>}[/tex]
d=453.557m

I think this should be right but I need someone to check for me because relativity confuses the s*** out of me..
Thanks for any help.
 
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Looks good to me. The observed length is the proper length contracted by gamma.
 
Thanks for looking Doc!
 

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