Relaxation time = displacement lifetime of fermi sphere?

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
1 reply · 4K views
neu
Messages
228
Reaction score
3

Homework Statement



I just want to clear this up, I am a little confused:

when an electric field is applied there is a force on the electron K-states thus displacing the fermi surface/sphere

Is the relaxation time ([tex]\tau[/tex])= lifetime of fermi sphere displacement

or is lifetime of displacement= reciprocal relaxation time

both are labebel as [tex]\tau[/tex] in my notes and related as below but how can they be the same?


Homework Equations



[tex]\sigma = \frac{n e^2 \tau}{m}[/tex] electrical conductivity

[tex]\rho = \frac{1}{\sigma}=\frac{m}{n e^2 \tau}[/tex] electrical resistivity
 
Last edited:
Physics news on Phys.org
Given the following data on copper, how do i calculate the resistivity?

Relaxation time: 2.50e10-14s
Density: 8940Kgm-3
molar mass: 63.5g

is there an equation for it.