Let x = 1.(adsbygoogle = window.adsbygoogle || []).push({});

Let n = Next Odd Number

Let y = Previous Sum

x^{2}= x

+3 = 4 = (1+x)^{2}

+5 = 9 = (3+x)^{2}

+n = n+y = (n-2 + x)^{2}

You could make a program to list all the squares without invoking the multiplication function or squaring function using a simple loop.

C++ Example:

#include "stdafx.h"

#include <iostream>

using namespace std;

int _tmain(int argc, _TCHAR* argv[])

{

cout<<"Squares: \n\n";

int sum=1,nextOdd=1; // Sum is Starting Integer Squared, Declared X in the For Loop below

for(int x=1;x<100;x++)

{

cout<<x<<" Squared is "<<sum<<"\n";

nextOdd+=2;

sum+=nextOdd;

}

system("pause");

}

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# [Remember Your Squares] Something I Found

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