Reminder on how to find eigenvectors

  • Context: Undergrad 
  • Thread starter Thread starter eherrtelle59
  • Start date Start date
  • Tags Tags
    Eigenvectors
Click For Summary
SUMMARY

This discussion focuses on finding eigenvectors for a specific matrix M given its eigenvalues. The matrix is defined as M = \begin{bmatrix} -σ & σ & 0 \\ ρ & -1 & 0 \\ 0 & 0 & -1 \end{bmatrix}. The eigenvalues identified are λ_1 = -1 and λ_2,3 = -(σ+1)/2 ± √((σ+1)² - 4σ(1-ρ)). The eigenvector corresponding to λ_1 is determined to be (0, 0, 1). The discussion highlights the need for further algebraic manipulation to derive the eigenvectors for λ_2 and λ_3, with a reference to the expected results in the related paper.

PREREQUISITES
  • Understanding of linear algebra concepts, specifically eigenvalues and eigenvectors.
  • Familiarity with matrix notation and operations.
  • Knowledge of solving linear equations.
  • Basic proficiency in algebraic manipulation.
NEXT STEPS
  • Review the process of calculating eigenvectors from eigenvalues in linear algebra.
  • Study the algebraic methods for solving systems of linear equations.
  • Explore the implications of eigenvectors in applications such as stability analysis and transformations.
  • Examine examples of eigenvector calculations for different types of matrices.
USEFUL FOR

Students and professionals in mathematics, physics, and engineering who are working with linear algebra concepts, particularly those needing to refresh their knowledge on eigenvector calculations.

eherrtelle59
Messages
25
Reaction score
0
Ok everybody, it's been awhile since I've taken linear algebra. I need some help dusting off the cobwebs. (I'm trying to follow this in a paper; this isn't a homework question, but I'll be glad to move it...)

Let's say I have a matrix M = \begin{bmatrix}
-σ & σ & 0 \\[0.3em]
ρ & -1 & 0 \\[0.3em]
0 & 0 & -1
\end{bmatrix} \

Ok, now I want to find the eigenvectors (I've already found the eigenvalues.

These are λ_1=-1 and λ_2,3 = -(σ+1)/2 +/- ( (σ+1)^2 -4σ(1-ρ))^.5

Now, to find the eigenvectors, I solve these equations:

(-σ-λ)e_1 +σ e_2 =0
ρ e_1 +(-1-λ) e_2 =0
(-1-λ) e_3 =0

Now, I see that the eigenvector for λ_1 is ( 0 0 1).

Now I'm stuck. How do I find the eigenvectors for the other two?

The result in the paper I'm reading says

λ_2,3 = (σ σ+λ_2 0 ) , (σ σ+λ_3 0 )

I forget how to do this...
 
Physics news on Phys.org
Essentially, just the way you did the first part, just much messier algebra!
 
Um...yes...

So, (-σ-λ)e_1 +σ e_2 =0

Looking at this and getting (σ+λ)e_1 =σ e_2, I would think the eigenvector is (σ+λ σ) not (σ+λ σ).
 

Similar threads

  • · Replies 33 ·
2
Replies
33
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
7K