- #1
eherrtelle59
- 25
- 0
Ok everybody, it's been awhile since I've taken linear algebra. I need some help dusting off the cobwebs. (I'm trying to follow this in a paper; this isn't a homework question, but I'll be glad to move it...)
Let's say I have a matrix M = \begin{bmatrix}
-σ & σ & 0 \\[0.3em]
ρ & -1 & 0 \\[0.3em]
0 & 0 & -1
\end{bmatrix} \
Ok, now I want to find the eigenvectors (I've already found the eigenvalues.
These are λ_1=-1 and λ_2,3 = -(σ+1)/2 +/- ( (σ+1)^2 -4σ(1-ρ))^.5
Now, to find the eigenvectors, I solve these equations:
(-σ-λ)e_1 +σ e_2 =0
ρ e_1 +(-1-λ) e_2 =0
(-1-λ) e_3 =0
Now, I see that the eigenvector for λ_1 is ( 0 0 1).
Now I'm stuck. How do I find the eigenvectors for the other two?
The result in the paper I'm reading says
λ_2,3 = (σ σ+λ_2 0 ) , (σ σ+λ_3 0 )
I forget how to do this...
Let's say I have a matrix M = \begin{bmatrix}
-σ & σ & 0 \\[0.3em]
ρ & -1 & 0 \\[0.3em]
0 & 0 & -1
\end{bmatrix} \
Ok, now I want to find the eigenvectors (I've already found the eigenvalues.
These are λ_1=-1 and λ_2,3 = -(σ+1)/2 +/- ( (σ+1)^2 -4σ(1-ρ))^.5
Now, to find the eigenvectors, I solve these equations:
(-σ-λ)e_1 +σ e_2 =0
ρ e_1 +(-1-λ) e_2 =0
(-1-λ) e_3 =0
Now, I see that the eigenvector for λ_1 is ( 0 0 1).
Now I'm stuck. How do I find the eigenvectors for the other two?
The result in the paper I'm reading says
λ_2,3 = (σ σ+λ_2 0 ) , (σ σ+λ_3 0 )
I forget how to do this...