1. The problem statement, all variables and given/known data An electron is released from rest in a weak electric field given by -2.8 x 10^-10 N/C [PLAIN]https://www.flipitphysics.com/Content/smartPhysics/Media/Images/Tipler/Symbols/jhatbold.gif. [Broken] After the electron has traveled a vertical distance of 1.9 µm, what is its speed? (Do not neglect the gravitational force on the electron.) Answer should be in mm/s. Any help towards setting up this problem or what formula to use will be greatly appreciated. 2. Relevant equations E=F/q F=qE+qV*B F= (1/4πE0)(q1q2/r^2) Fnet=Fg=ma=mg Work Done = F*d = 1/2(mv^2) 3. The attempt at a solution I don't really know where to start, this is the last problem on my assignment and I only have a few attempts left, we did not go over this in class yet and our class uses "Flipit Physics" videos instead of a book. I tried Fe=qE =(1.602x10^-19)(-2.8x10^-10) = -4.4856x10^-29 then a = Fe/m = -4..572477064 x 10^-31 which was wrong I also tried Work Done = F*d = 1/2(mv^2) and solved for v but that was also wrong.