Resolvant Power of a Dİffraction Grating

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Homework Help Overview

The discussion revolves around the concept of resolvent power (R) of a diffraction grating, specifically focusing on its definition and the relevant equations involved.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to clarify the formula for resolvent power and relates it to the number of slits in the grating. Some participants question the completeness of the provided equations and express dissatisfaction with external resources.

Discussion Status

The discussion appears to be ongoing, with participants seeking further clarification and expressing a desire for more engagement. There is no explicit consensus on the interpretation of the equations or the adequacy of the resources referenced.

Contextual Notes

Participants are navigating the definitions and relationships within the context of diffraction gratings, with some expressing frustration over the lack of responses and clarity.

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Homework Statement


What is the resolvent power (R) of a diffraction grating?


Homework Equations


R=(Δλ)/λ
asin(θ)=mλ

The Attempt at a Solution


as we all know answer is Nm here N is the number of slits
there is something starting with
a sin(θ)(Δθ)=mΔλ but it gets stuck
 
Physics news on Phys.org
http://hyperphysics.phy-astr.gsu.edu/hbase/phyopt/gratres.html"
 
Last edited by a moderator:
i had checked that but it is not much satisfying
 
come on guys its been a long time, not anyone?
 

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