Resolvant Power of a Dİffraction Grating

  • Thread starter Thread starter sigmaro
  • Start date Start date
  • Tags Tags
    Grating Power
AI Thread Summary
The resolvent power (R) of a diffraction grating is defined by the equation R = Δλ/λ, where Δλ is the change in wavelength and λ is the wavelength. The relationship also involves the number of slits (N) in the grating, indicating that R is proportional to N. A discussion participant references the equation a sin(θ)(Δθ) = mΔλ but expresses difficulty in applying it. They seek further clarification or assistance on this topic, indicating a need for more detailed explanations. The conversation highlights the complexities involved in understanding diffraction grating and its resolvent power.
sigmaro
Messages
24
Reaction score
0

Homework Statement


What is the resolvent power (R) of a diffraction grating?


Homework Equations


R=(Δλ)/λ
asin(θ)=mλ

The Attempt at a Solution


as we all know answer is Nm here N is the number of slits
there is something starting with
a sin(θ)(Δθ)=mΔλ but it gets stuck
 
Physics news on Phys.org
http://hyperphysics.phy-astr.gsu.edu/hbase/phyopt/gratres.html"
 
Last edited by a moderator:
i had checked that but it is not much satisfying
 
come on guys its been a long time, not anyone?
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top