- #1

r_swayze

- 66

- 0

*If your calculator has overflow issues with this problem, you can use this identity to solve for K:*

if log(K) = x + y then K = 10

Problem:

log(K) = 127.702

K = 5.04316 * 10"

if log(K) = x + y then K = 10

^{x}* 10^{y}Problem:

log(K) = 127.702

K = 5.04316 * 10

^{127}Doesn't K = 10

^{127}?

Where are they getting the 5.04316 from? How are they using that specified identity?