Resolving Forces for Composite Shape: Cone with Attached Ring | Mass: 52kg

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Homework Help Overview

The problem involves a composite shape consisting of a cone and an attached ring, with a total mass of 52 kg. The cone has a mass of 22 kg, while the ring has a mass of 30 kg. The shape is positioned at an angle of 21 degrees from the horizontal, and the task is to find the two forces acting vertically upwards.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss finding the center of gravity (CG) using a weighted average approach and resolving forces into vertical and horizontal components. There are questions about the torque and equilibrium conditions, particularly regarding the total torque around any point. Some participants suggest taking moments about specific points to find the forces, while others inquire about determining necessary distances for calculations.

Discussion Status

The discussion is active, with participants providing various insights and suggestions. Some have offered guidance on considering torque and moments, while others are exploring the geometric relationships necessary for solving the problem. There is no explicit consensus, but multiple interpretations and approaches are being examined.

Contextual Notes

Participants note that the forces are not aligned with the centerline of the CG, which introduces complexity in calculating the perpendicular distances required for moment calculations. There is also mention of needing to analyze the forces at different angles as the cone is rotated.

dennis1984
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Homework Statement


there is a composite shape (cone with ring attached at open end) total mass 52kg,cone m=22kg, ring=30kg find the 2 forces acting vertically upwards. the shape is lying on its side 21deg from the horizontal.

Homework Equations


(xtotal x mtotal) = (xcone x mcone) + (xring x mring)
balance forces ( up=down and left=right)

The Attempt at a Solution



find the CG using (xtotal x mtotal) = (xcone x mcone) + (xring x mring)
resolve forces into verical and horizontal components
balance forces
the problem I am having is that one force is acting through the centrline at the tip of the cone and the other force is acting at the bottom point of the ring ( see pic)

please help i am pulling my hair out!
 

Attachments

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Also consider the torque. What should the total torque around any point be, if the object is at equilibrium? Then you have enough info to find the forces.
 
See my sketch, can you determine distances L_1 and L_2? If so take moments about points A and B and the problem is done?
 

Attachments

  • cg046.jpg
    cg046.jpg
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Yes, if you have distances L_1 and L_2, the forces can be found by considering the moments about A and B.

Distances L_1 and L_2 can be found using geometry. The pdf you attached in your original post has all the information needed.
 
thank you very much for your replies,


for equilibrium: clockwise moments must equal anti clockwise moments

and because the forces are not perpendicular or parallel to the centreline of the CG the distances L1 and L2 must be the perpendicular distances from the CG to the line of action of the forces.

i have to basically work out the forces at various angles until the cone is vertical to make sure the forces shown in the diagram do not exceed a certain limit as the object is rotated so the same concept of resolving the forces into components(because of the angle that the object is at) and then taking moments will apply.
 

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