2-D Motion Problem with 2 masses attached by a string.

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SUMMARY

The discussion focuses on solving a 2-D motion problem involving two masses, m1 = 3.7 kg and m2 = 3.3 kg, connected by a string on a frictionless surface. A force of 15 N is applied at an angle of 18 degrees above the horizontal to mass m2. The acceleration of the blocks is calculated to be 4.321 m/s², while the tension in the string requires clarification due to nomenclature confusion in the initial attempt. The correct application of free body diagrams (FBD) is essential for accurate calculations.

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1. Homework Statement

Two blocks of masses m1 = 3.7 kg and m2 = 3.3 kg are connected by a string as shown in the figure above. The horizontal surface is frictionless. A 15 N force directed at 18 degrees above the horizontal acts on m2.
Determine the acceleration of the blocks and the tension in the string.

Homework Equations


m1=3.7kg
m2=3.3kg
F= 15N
θFo=18°
Ff=0

The Attempt at a Solution



Snapshot.jpg

Wm2= 9.8m/s^2x3.3kg = 32.34N

∑Fx= m⋅ax


-Fx+M1 =m⋅ax
-(cos 18°⋅15N)+M1 = 3.3kg⋅-ax
-14.26N+M2 =3.3kg⋅-ax
ax+M1 =4.321 m/s2

∑Fy=m⋅ay

+Fy+FN -Wm2 =m⋅ay

I'm kind of stuck after this..
 
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Where's your FBD for mass m1?

Your nomenclature is kind of confusing. You use M1 for the tension force and there is also an m1 mass. Then you switch back and forth between M1 and M2 which I assume is just a typo.
 

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