Resolving forces: Mass on a string

[thebosonbreaker]

Homework Statement

A mass of 50 grams hangs in equilibrium on a string. The mass is pulled aside and upwards by a force of 0.3N which makes an angle of 30° with the horizontal. Find the angle that the string makes with the vertical and the tension in the string.

Homework Equations

Body is in equilibrium, so I will need to resolve forces (tension and weight).

The Attempt at a Solution

For the first part of the question (find the angle that the string makes with the vertical):
I do not understand why this is not 60° - the string will move in the same direction as the 0.3N force applied to it, so if it makes an angle of 30° with the horizontal (the angle between 'horizontal'/'vertical' being a right angle), the angle made with the vertical must be: 180 - (90 + 30) = 60°. Could somebody please explain why this is not the case and how to find the angle?

For the second part of the question (finding the tension in the string):
Resolving horizontally I have that: Tcos30° = 0.3 [the horizontal component of tension equals the horizontal force applied]
Resolving vertically I have that: Tsin30° = mg = 0.05g
These both lead to different answers for T.

Could somebody clraify this problem? I'm having a bit of a hard time with it.
Thanks a lot in advance, your help will be greatly appreciated!

 

[ehild]

Homework Statement

A mass of 50 grams hangs in equilibrium on a string. The mass is pulled aside and upwards by a force of 0.3N which makes an angle of 30° with the horizontal. Find the angle that the string makes with the vertical and the tension in the string.

Homework Equations

Body is in equilibrium, so I will need to resolve forces (tension and weight).

The Attempt at a Solution

For the first part of the question (find the angle that the string makes with the vertical):
I do not understand why this is not 60° - the string will move in the same direction as the 0.3N force applied to it, so if it makes an angle of 30° with the horizontal (the angle between 'horizontal'/'vertical' being a right angle), the angle made with the vertical must be: 180 - (90 + 30) = 60°. Could somebody please explain why this is not the case and how to find the angle?

For the second part of the question (finding the tension in the string):
Resolving horizontally I have that: Tcos30° = 0.3 [the horizontal component of tension equals the horizontal force applied]
Resolving vertically I have that: Tsin30° = mg = 0.05g
These both lead to different answers for T.

Could somebody clraify this problem? I'm having a bit of a hard time with it.
Thanks a lot in advance, your help will be greatly appreciated!

In equilibrium, the string aligns in the direction of the resultant of gravity and the applied force.

 

[PeroK]

If the object were heavy enough the applied force might only move it a very short distance. No where near 60 degrees.

 

[gneill]

The thread title mentions a spring. I don't see any mention of a spring in the problem itself.

Edit: Does the thread title need correction?

 

[Chestermiller]

Have you drawn a free body disgram showing the forces acting on the mass, or do you feel like you have advanced beyond the point where you need to use free body diagrams?