Hello, We're studying sound waves in Physics and my instructor did a quick demo showing resonance with a tuning fork. He showed that when a tuning fork is struck and then connected to a resonating cavity, the sound is substantially amplified. I understand that resonance arises due to sound waves bouncing back and forth in the cavity and amplifying themselves, but I'm having a hard time understanding the greater intensity of sound waves that my ear perceives in terms of energy conservation. When the tuning fork is not connected to the resonant cavity, the sound is relatively tinny. When it is connected to the cavity, the sound is much greater. Doesn't the latter scenario seem to imply that the tuning fork is somehow giving off energy at a greater rate to produce the greater intensity of sound when connected to the resonant cavity? Ultimately, whether the tuning fork is connected to a cavity or not, the energy that it gives off as sound waves must come from the deformation of the tuning fork (which is initially elastic potential energy coming from striking and deforming the tuning fork... right?) from the initial strike. It seems to me that the entire object (tuning fork + cavity) is giving off much more energy when struck in this case, but I can't see how resonance would account for this. What am I missing here? Thanks, Alexander.