Resonance in a Mechanical System

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SUMMARY

The discussion centers on calculating the length of a spring in a mechanical system where a mass m is attached to a massless spring with force constant k, revolving with angular frequency ω. The key equations involved are F = ω² * l * m and FSpring = k * l. The solution requires recognizing that the spring's unstretched length l0 plays a crucial role in determining the elastic force when the spring is at its natural length. The correct approach involves equating the centripetal force to the spring force while considering the spring's unstretched length.

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  • Understanding of Hooke's Law and spring constants
  • Familiarity with circular motion and centripetal force
  • Basic knowledge of angular frequency and its applications
  • Ability to manipulate algebraic equations for solving variables
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  • Study the derivation of Hooke's Law in mechanical systems
  • Learn about the relationship between angular frequency and centripetal acceleration
  • Explore the concept of spring potential energy and its implications
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Homework Statement


A mass m is attached to one end of a massless spring with a force constant k and an unstretched length l0. The other end of the spring is free to turn about a nail driven into a frictionless, horizontal surface. The mass is made to revolve in a circle with an angular frequency of revolution ω.
Question:
Calculate the length l of the spring as a function of ω.

Homework Equations


F = ω2*l*m
FSpring = k*l


The Attempt at a Solution


Fspring = Fcirc
-k*l = ω2*l*m

The issue I am having is how to get L by itself, or what I am supposed to do with l0. Can someone guide me on where I should head in order to solve this problem? The issue is l cancels when I divide, unless I am supposed to use l0 in place of l
Thanks!
 

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You are using "l" to designate two different things.
If "l" in the first equation is the total length of the spring (radius of the circle), then the elastic force is not correct. The force does not depend on the total length.
What is the force when the length is lo?
 
The force when length lo is just omega^2 *m*lo correct?
 
No. What is the elastic force ("produced" by the spring) when the spring's length is lo?
Hint: at lo the spring is unstretched.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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