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Resultant force on the piston at the end of stroke

  1. Jun 16, 2014 #1
    1. The problem statement, all variables and given/known data

    my question is on part a , the ans is 4260N . but my answer is double of the ans given. why i'm wrong? the working is shown in the photo.

    2. Relevant equations



    3. The attempt at a solution
     

    Attached Files:

  2. jcsd
  3. Jun 16, 2014 #2
    The net force acting in an SHM is F=-kx...

    You can find k by using the formula of frequency of an SHM.
     
  4. Jun 17, 2014 #3
    You've maybe put 0.12 m as the crank radius when it should be 0.06 m
    r = crank radius = 0.06 metres
    w = crank rotation rate = 376.99112 rad / sec

    Find the tangential velocity (v) from :
    v = w * r
    v = 376.99112 * 0.06
    v = 22.619 m/s (ANSWER b)

    Find the centripetal acceleration (a) :
    a = v ² / r
    a = 8,527.338 (m/s)/s

    The decelerating force (f) = m * a
    f = 0.5 * 8,527.338 N
    f = 4,263.67 N (ANSWER a)
     
  5. Jun 17, 2014 #4
    Dude, complete solutions aren't allowed here... :rolleyes:
     
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