- #1
Resultant force on the piston at the end of stroke
- Thread starter kelvin macks
- Start date
Click For Summary
Homework Help Overview
The discussion revolves around calculating the resultant force on a piston at the end of its stroke, specifically focusing on part a of the problem. Participants are examining the discrepancies in their calculations compared to a provided answer of 4260N.
Discussion Character
- Exploratory, Assumption checking, Problem interpretation
Approaches and Questions Raised
- Participants are questioning their calculations, particularly regarding the crank radius used in their equations. There is a mention of using the formula for net force in simple harmonic motion and the relationship between tangential velocity and centripetal acceleration.
Discussion Status
Some participants have provided calculations and suggested potential errors in the original poster's assumptions, particularly regarding the crank radius. There is an ongoing exploration of the problem with no explicit consensus reached yet.
Contextual Notes
Participants are working under the constraints of homework rules that discourage complete solutions, leading to a focus on reasoning and verification of assumptions rather than final answers.
![IMG_20140616_083027[1].jpg](/data/attachments/54/54326-ad929cd2ee10d39989521d3c9b47e991.jpg?hash=rZKc0u4Q05)
- #2
sankalpmittal
- 785
- 27
kelvin macks said:
The net force acting in an SHM is F=-kx...
You can find k by using the formula of frequency of an SHM.
- #3
dean barry
- 311
- 23
You've maybe put 0.12 m as the crank radius when it should be 0.06 m
r = crank radius = 0.06 metres
w = crank rotation rate = 376.99112 rad / sec
Find the tangential velocity (v) from :
v = w * r
v = 376.99112 * 0.06
v = 22.619 m/s (ANSWER b)
Find the centripetal acceleration (a) :
a = v ² / r
a = 8,527.338 (m/s)/s
The decelerating force (f) = m * a
f = 0.5 * 8,527.338 N
f = 4,263.67 N (ANSWER a)
r = crank radius = 0.06 metres
w = crank rotation rate = 376.99112 rad / sec
Find the tangential velocity (v) from :
v = w * r
v = 376.99112 * 0.06
v = 22.619 m/s (ANSWER b)
Find the centripetal acceleration (a) :
a = v ² / r
a = 8,527.338 (m/s)/s
The decelerating force (f) = m * a
f = 0.5 * 8,527.338 N
f = 4,263.67 N (ANSWER a)
- #4
sankalpmittal
- 785
- 27
dean barry said:
Dude, complete solutions aren't allowed here...
