1. The problem statement, all variables and given/known data A man pushing a toy car causes it to undergo 2 displacements. The first has a magnitude of 150 cm and makes an angle of 120degrees with the positive x axis. The resultant displacement has a magnitude of 140 cm and is directed at an angle of 35 degrees at the positive x axis. Find the magnitude and direction of the second displacement. 3. The attempt at a solution Displacement A + Displacement B = Displacement R B = R - A R = Rx + Ry R = 140cos35i + 140sin35j 180° - 120° = 60 A = Ay + Ax A = 150sin60j - 150cos60i (2nd Quad?? Not too sure if need to put negative here) Hence: B = Rx + Ry - (Ay + Ax) B = 140cos35i + 140sin35j - (150sin60j - 150cos60i) B = (140cos35 +150cos60)i + (140sin35 - 150sin60)j B = sqrt( Bi^2 + Bj^2 ) B = 196 To find Direction tetha = taninverse( (140sin35 - 150sin60)/ (140cos35 +150cos60) ) tetha = -14.65 degrees ?? weird??