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[Moderator's note: No template because the thread had attracted a fair number of responses before being moved out of Classical]

v₁'=[(m₁-m₂)/(m₁+m₂)]*v₁

v₁'=[(0.8-0.6)/(0.8+0.6)]*7

v₁'=1

v₂'=[(2* m₁)/(m₁+m₂)]*v₁

v₂'=[(2* 0.8)/(0.8+0.6)]*7

v₂'=8

vₓ₁= v₁' + -5

vₓ₁= 1 + -5

vₓ₁= -4 m/s

vₓ₂= v₂' + -5

vₓ₂= 8 + -5

vₓ₂= 3 m/s

**Hey it's my first post, so I apologize in advance if this is under the wrong forum category... I am just wondering if I did I do this right? If not can you please show me what I've done wrong and show your corrected math.**

Thank you!Thank you!

*In an elastic head-on collision, a 0.60 kg cart moving at 5.0 m/s [W] collides with a 0.80 kg cart moving at 2.0 m/s [E].*

What is the final velocity of each cart after the collision?What is the final velocity of each cart after the collision?

**First I changed the frame of reference...***FROM*[0.8 kg @ 2 m/s]**----> <----**[0.6 kg @ -5 m/s]*TO*[0.8 kg @ 7 m/s]**----> <----**[0.6 kg @ 0 m/s]*(are these equations right?)*

**My work...**v₁'=[(m₁-m₂)/(m₁+m₂)]*v₁

v₁'=[(0.8-0.6)/(0.8+0.6)]*7

v₁'=1

v₂'=[(2* m₁)/(m₁+m₂)]*v₁

v₂'=[(2* 0.8)/(0.8+0.6)]*7

v₂'=8

*Final Velocities*vₓ₁= v₁' + -5

vₓ₁= 1 + -5

vₓ₁= -4 m/s

vₓ₂= v₂' + -5

vₓ₂= 8 + -5

vₓ₂= 3 m/s

**The final velocity for the 0.8 kg is 4 m/s [W]**

The final velocity for the 0.6 kg is 3 m/s [E]

The final velocity for the 0.6 kg is 3 m/s [E]

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