Resultant Velocity of sailing boat

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Homework Help Overview

The problem involves determining the resultant velocity of a sailing boat moving at a specific bearing and speed, while also accounting for a current flowing in a different direction. The context is rooted in vector addition and the application of trigonometric principles to resolve the velocities.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the setup of the problem, including the angles and directions of the boat and current. There is an exploration of the triangle formed by the vectors and attempts to apply the cosine rule. Questions arise regarding the accuracy of the drawn vectors and the correct interpretation of angles.

Discussion Status

The discussion is ongoing, with participants providing guidance on how to properly represent the vectors for the boat and current. There is a focus on understanding the graphical method of vector addition, specifically the head-to-tail method, which has been introduced to one participant.

Contextual Notes

There is mention of confusion regarding the angles and the drawing of vectors, indicating a need for clarity in visual representation. The original poster expresses difficulty in achieving the expected resultant speed, suggesting that assumptions about the setup may need to be revisited.

Purity
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Homework Statement



A boat is sailing on a bearing of 120° and has a speed of 4ms^-1 relative to water. A current has a speed of 2ms^-1 and flows south west.

Find the resultant speed of the boat

2. The attempt at a solution

I've been stuck on this question for an hour now and can't figure out why I'm not getting the correct answer of 3.98ms^-1

If the current is going SW at 225°, (180°+45°), then i have the triangle vbc where b is 2ms^-1 and c is 4ms^-1 and the angle A=105° (225°-120°). (opposite the resultant velocity side v).

I then tried to use the cosine rule which gave me v=4.913...ms which i assumed should've worked.

can someone help me please, I've hit a brick wall again...
 
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Purity said:
If the current is going SW at 225°, (180°+45°), then i have the triangle vbc where b is 2ms^-1 and c is 4ms^-1 and the angle A=105° (225°-120°). (opposite the resultant velocity side v).
Your angle is wrong. Draw the vector representing the current at 225°. Then from its tip, draw the vector representing the boat's velocity with respect to that current. (You want your triangle to represent the vector sum.) What's the angle between those two side of the triangle?
 
I still don't understand, what I've got drawn is the vertical North axis and line for the boat coming off at 120 degrees and then another line for the current coming off at 225 degrees but they share the same vertex. have i drawn it wrong?
 
Last edited:
Purity said:
I still don't understand, what I've got drawn is the vertical North axis and line for the boat coming off at 120 degrees and then another line for the current coming off at 225 degrees but they share the same vertex. have i drawn it wrong?
Looks like you've drawn the vectors with a common origin. Now you have to draw them to represent their sum. So starting with the current, draw its vector as you have done. Then draw the vector representing the boat's speed at 120 degrees starting with its tail at the head of current vector. That's the triangle you want.

(This is often called the 'head to tail' method of graphically adding vectors. The tail of the boat vector starts at the head of the current vector.)
 
Got it, thanks :) I've never heard of a head to tail method before but thank you! the book never mentioned it.
 

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