Reverse-Biased Diodes: Overheating, Spoilage, and Repair

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Reverse-biased diodes can become permanently damaged due to overheating when subjected to high voltage, leading to excessive heat dissipation at the junction. This overheating disrupts the crystal structure of the diode, rendering it unusable, although the atoms themselves remain unchanged. If the current is limited by surrounding circuitry, the diode may survive reverse breakdown, especially if it is avalanche rated. Avalanche-rated diodes can behave like Zener diodes, but excessive heat can still cause localized melting and shorting. Devices like Schottky rectifiers may fail due to punch-through, which creates visible damage at the failure point, prompting manufacturers to incorporate protective zener devices.
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When a diode is reverse biased by a very large voltage, then it will be spoiled permanently due to overheating.
Then what is happening inside the diode?
Why will it spoil? Is that because the silicon atom inside the spoiled diode is changed? Can a spoiled diode be fixed?
Thank you.
 
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It will be permanently damaged unless you include a large series resistance to limit the current. Otherwise, reverse breakdown can cause a small region to dissipate excessive heat, causing the diode to be ruined. In that case, the only fix is to throw it away and solder in a new one.
 
NascentOxygen said:
reverse breakdown can cause a small region to dissipate excessive heat, causing the diode to be ruined.
What do you mean by 'to dissipate excessive heat'? So when the diode is spoiled what makes it can't be reused eg. any atoms or bond will permanently changed ?
Thanks.
 
What do you mean by 'to dissipate excessive heat'? So when the diode is spoiled what makes it can't be reused eg. any atoms or bond will permanently changed ?

Yes that is pretty well what he means, except that the atoms themselves are not changed - heat alone cannot do that - but the crystal structure that makes a junction is disrupted.

Note also that he said a small area ie the important small area at the junction - not the whole crystal.
 
When the diode "avalanches," which simply means that it starts pulling current due to excess voltage, it may or may not break depending on whether the current is sufficiently limited by the surrounding circuitry and whether the diode is "avalanche rated."
Vendors will generally note in their data sheet whether a device is avalanche rated. Avalanche rated devices will act like zener diodes and will only die if too much heat accumulates at some point on the die. Then, localized melting will typically poison the junction and the diode will usually be shorted. That is, unless sufficient current is available. Then, the device and package will typically burst apart as the current burns it open.
Some devices, like Schottky rectifiers die due to punch through. This is somewhat like an ESD failure in appearance. It occurs due to a sudden breakdown of the devices ability to hold off voltage in one place. When this happens, you can see a physical pit in the metallization at the point of failure. To offset the occurrence of this problem, manufacturers will build in a zener device in the structure. This is typically about the outer edge and serves to avalanche at a lower voltage, thus protecting from punch through.

If your really interested in rectifiers, their idiosyncrasies, and the inside on manufacturers, I can give you more than you'd probably care to hear :), so feel free to message.
 
I am trying to understand how transferring electric from the powerplant to my house is more effective using high voltage. The suggested explanation that the current is equal to the power supply divided by the voltage, and hence higher voltage leads to lower current and as a result to a lower power loss on the conductives is very confusing me. I know that the current is determined by the voltage and the resistance, and not by a power capability - which defines a limit to the allowable...

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