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Reversible Clapeyron cycle efficiency

  1. Feb 18, 2014 #1
    1. The problem statement, all variables and given/known data
    The Clapeyron cycle efficiency is similar to the Carnot cycle except that two adiabatic paths are replaced with isobaric processes

    a) based on the above information, draw a Clapeyron cycle.

    b)Derive the efficiency of the reversible Clapeyron cycle


    2. Relevant equations


    e=1-(QL/QH)
    3. The attempt at a solution

    part a) see attachment

    b) I really dont know where to start with this,

    I am thinking of using QL=nCp(Td-Ta) & QH=nCp(Tc-Tb) as a starting point.

    Any help would be greatly appreciated.
     

    Attached Files:

  2. jcsd
  3. Feb 18, 2014 #2

    Andrew Mason

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    Science Advisor
    Homework Helper

    You have the right idea but you are missing the heat flow in the isothermal parts. Use the first law to write the expression for heat flow in/out for the isothermal parts and add that to the heat flows you have found at constant P to find the total heat flow in (Qh) and out (Qc) and use your expression for efficiency.

    AM
     
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