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Reversible Clapeyron cycle efficiency

  1. Feb 18, 2014 #1
    1. The problem statement, all variables and given/known data
    The Clapeyron cycle efficiency is similar to the Carnot cycle except that two adiabatic paths are replaced with isobaric processes

    a) based on the above information, draw a Clapeyron cycle.

    b)Derive the efficiency of the reversible Clapeyron cycle

    2. Relevant equations

    3. The attempt at a solution

    part a) see attachment

    b) I really dont know where to start with this,

    I am thinking of using QL=nCp(Td-Ta) & QH=nCp(Tc-Tb) as a starting point.

    Any help would be greatly appreciated.

    Attached Files:

  2. jcsd
  3. Feb 18, 2014 #2

    Andrew Mason

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    Homework Helper

    You have the right idea but you are missing the heat flow in the isothermal parts. Use the first law to write the expression for heat flow in/out for the isothermal parts and add that to the heat flows you have found at constant P to find the total heat flow in (Qh) and out (Qc) and use your expression for efficiency.

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