Reversible Clapeyron cycle efficiency

[garyd]

Homework Statement

The Clapeyron cycle efficiency is similar to the Carnot cycle except that two adiabatic paths are replaced with isobaric processes

a) based on the above information, draw a Clapeyron cycle.

b)Derive the efficiency of the reversible Clapeyron cycle

Homework Equations

e=1-(QL/QH)

The Attempt at a Solution

part a) see attachment

b) I really don't know where to start with this,

I am thinking of using QL=nCp(Td-Ta) & QH=nCp(Tc-Tb) as a starting point.

Any help would be greatly appreciated.

 

[Andrew Mason]

Homework Statement

The Clapeyron cycle efficiency is similar to the Carnot cycle except that two adiabatic paths are replaced with isobaric processes

a) based on the above information, draw a Clapeyron cycle.

b)Derive the efficiency of the reversible Clapeyron cycle

Homework Equations

e=1-(QL/QH)

The Attempt at a Solution

part a) see attachment

b) I really don't know where to start with this,

I am thinking of using QL=nCp(Td-Ta) & QH=nCp(Tc-Tb) as a starting point.

Any help would be greatly appreciated.

You have the right idea but you are missing the heat flow in the isothermal parts. Use the first law to write the expression for heat flow in/out for the isothermal parts and add that to the heat flows you have found at constant P to find the total heat flow in (Qh) and out (Qc) and use your expression for efficiency.

AM