First, I calculated the number of moles of glucose.
n = m / M
n = 1.8 / 180
n = 0.01 moles of glucose
So I checked the combustion reaction.
1 C6H12O6 + 6 O2 -> 6 CO2 + 6 H20
1 + 6 -> 6 + 6
0.01 + 0.06 -> 0.06 + 0.06
I considered the number of moles at the end of the reaction.
Consider a system formed by two phases of a substance that consists of a single class of molecules. Determine the specific heat ##c## of a vapor pressure and temperature ##p## ##T## on the curve of liquid-vapor equilibrium. Consider the steam as an ideal gas.
Hello everyone, I'm doing revision for a final exam in Thermodynamics and i found this exercise i can't solve:
A particular material has a latent heat of vaporization Δh, constant along the coexistence curve. One mole of this material exists in two.phase (liquid-vapor) equilibrium in a...