Review My Work: Arranging Atoms & Ions by Radius

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SUMMARY

This discussion focuses on the arrangement of atoms and ions by radius and the molecular geometry of various compounds. The BeF2 molecule is linear due to sp hybridization, while SF2 is angular because of the presence of lone pairs. The hybridization of one d, one s, and two p orbitals results in dsp2 hybrid orbitals. The comparison of C20H40 and C4H8 illustrates the relationship between molecular weight and physical state, with C20H40 being a solid due to stronger intermolecular forces. The correct order of increasing radius for Cl, S2-, K, K+, and O is O, Cl, K+, S2-, K.

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RPN
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Okay I did my work but if someone would be so kind as to look at it and see if I am understanding.
Questions
1. Explain why you would expect a BeF2 molecule to be linear but an SF2 molecule to be angular?
BeF2 forms an ionic bond with 2 single bonds. Since Be is in group IIA it forms two sp hybrid orbitals. The farthest away the pairs can be is 180 o angle, making it linear. SF2 forms two covalent bonds with two F atoms. Having four pairs of electrons around the S atom the farthest away they can be is in an angular shape.

2a) How would you designate the hybrid orbitals formed by "mixing" one d, one s and two p orbitals?
a) When mixing one d orbital, one s orbital and 2 p orbitals you get dsp2.
b) How many of the hybrid orbitals would be formed by the mixing?
b) The number you put in is the number you get as a result. So in this case we put in 4 orbitals we then get 4 hybrid orbitals.

3. Explain why C20H40 is a solid at 25degcel, while C4H8 is a gas at 25degcel?
39. C20H40 is a solid at 25o C because has more electrons. With more electrons you get more forces that can hold the lattice pattern together. C4H8 is a gas at 25o C because the bonds are weak and that gives this compound a low boiling temp.

4.Arrange the following atoms or ions in order of increasing radius:
Cl, S2-, K, K+, O
if an explanation for the position of S2- in relation to the atom or ion in front and behind it.
OK I have:31.
O, S2-, K+, Cl ,K
------------------>
increasing radius

S2- is smaller than K+ in this case because it has a configuration the same as Ar, a noble gas. Moving horizontally in the periodic table the radius decreases in size.
S2- is bigger than Cl because?
If someone would look over my answers and see if i am correct or even close.
Thank you
 
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2 is entirely correct.1 is okay.Indeed the nonbonding pairs distort the linear structure.At 3,there's a connection between the molar mass and the the # of atoms in the hydro-carbide.

4.The order should be

O,Cl,K^{+},S^{2-},K

------------------------------>
increasing ionic/atomic radius.

1.The # of electrons and the # of shells are the main criteria.
2.For isoelectronic configurations,the largest radius corresponds to the smaller nuclear charge.

Daniel.
 
oops.

Sorry about that, I should read better before posting.. I understand it now
 
Last edited:

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