Two resistors, when conected in series have a total resistance of 12.9KOhms, and when connected in parallel a combined resistance of 2.988KOhms. Derive the value of the individual resistors.
R = R1+R2 ---Series
1/R = 1/R1 + 1/R2
The Attempt at a Solution
Ive tried a few different things but i don't get the right answer :S