Revolution of moon and satellite

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SUMMARY

The discussion centers on calculating the distance from the Earth's center to a geostationary satellite in relation to the Earth-Moon distance. The Earth-Moon distance is approximately 384,400 kilometers, and the geostationary satellite orbits at about 35,786 kilometers above the Earth's equator. The cycle of revolution for the Moon around the Earth is noted as 27 days, which is relevant for understanding orbital mechanics. Kepler's Laws are suggested as a foundational concept for solving the problem.

PREREQUISITES
  • Understanding of Kepler's Laws of planetary motion
  • Basic knowledge of orbital mechanics
  • Familiarity with geostationary satellite characteristics
  • Concept of distance measurement in astronomy
NEXT STEPS
  • Research the application of Kepler's Laws in satellite motion
  • Learn about the calculations involved in determining satellite orbits
  • Explore the differences between geostationary and geosynchronous satellites
  • Investigate the gravitational forces affecting satellite positioning
USEFUL FOR

Astronomy students, aerospace engineers, and anyone interested in satellite technology and orbital dynamics will benefit from this discussion.

Asla
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Homework Statement


What multiple of the distance between the centre of the Earth and that of the moon is the distance between the centre of the Earth and a geostationary satellite which above a fixed location on the equator?Take the cycle of revolution to the moon around the Earth to be 27 days

The Attempt at a Solution


I do not know how to start.An idea please?
 
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Kepler's Laws?

What is the time period of a geostationary satellite?

ehild
 

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