Rewrite equation (rationalize denominator)

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Homework Help Overview

The discussion revolves around a problem in College Algebra concerning the manipulation of an equation involving a square root in the denominator. The original poster seeks to rewrite the equation M = M_o / √(1 - v²/c²) in a different form, specifically M = M_oc√(c² - v²) / (c² - v²).

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to rationalize the denominator and shares their progress, noting confusion about transforming one expression into another. Some participants question the accuracy of the original equation and offer suggestions for manipulation, such as splitting terms within the square root.

Discussion Status

The discussion has seen some productive exchanges, with participants providing pointers and corrections. The original poster acknowledges a mistake and expresses appreciation for the feedback received, indicating a shift towards clarity in their understanding.

Contextual Notes

Participants note the original poster's prior experience with similar problems, which may have influenced their approach to this equation. There is a mention of a common mistake related to rationalizing denominators, highlighting the learning process involved.

jkristia
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Homework Statement



I just started on College Algebra (online) and completed the homework for the first chapter.
There is one question which is not part of the homework, but it looks interesting so I gave it a try, but I get stuck at some point and would like some pointers of how to solve it

The questions is

Show that the equation
[tex]M = \frac {M_o} {\sqrt{1 - \frac{v^2}{c^2}}}[/tex]


can be written in the form
[tex]M = \frac {M_oc \sqrt{c^2-v^2} } {c^2-v^2}[/tex]

Homework Equations




The Attempt at a Solution



I tried to rationalize the denominator and got to

[tex]M = \frac {M_oc^2 \sqrt{1 + \frac{v^2}{c^2}} } {c^2-v^2}[/tex]

But I can't see how to turn

[tex]M_oc^2 \sqrt{1 + \frac{v^2}{c^2}}[/tex]

into

[tex]M_oc \sqrt{c^2-v^2}[/tex]


Any help is appreciated.


Jesper
 
Last edited:
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Hi Jesper! :smile:

(have a square-root: √ :wink:)
jkristia said:
M = M0c2 sqrt(1 + v2/c2) / (c2 - v2)

erm :redface: … where did that "+" come from? :wink:
 
Hi Tim,
Just spend the last 1/2 hour trying to enter the equation using Latex.

argh ... found my mistake, thank you for pointint it out :)

edit - actually, that was REALLY embarrassing, next time I will triple check before asking
 
Last edited:
jkristia said:
I just started on Colage Algebra (online)
That would be College Algebra.

Collage is a word in English, but it doesn't have anything to do with education. Colage is not a word in English. College is the word you want.
 
>>That would be College Algebra.

yes of course :)
 
Try splitting your [tex]c^2[/tex] that is outside of the square root, into [tex]c*c[/tex] and see where you can go from there =)
 
Thanks your your help, but I found the problem as soon as tiny-tim pointed out the '+'.
This was one of my typical 'duh' mistakes. I had been doing exercises where the denominator was of form

(sqrt(a) - b)

so I had been rationalizing by multiplying with (sqrt(a) + b) in the denominator, and I did the same with this one, so that is where the '+' came from.

Of course in this case I just need to square the squareroot, and once I realized that it was straight forward.

Jesper
 

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