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**[SOLVED] ridid body equilibrium, tension in hanging wires**

**1. Homework Statement**

A 60.0cm, uniform, 49.0N shelf is supported horizontally by two vertical wires attached to the sloping ceiling. A very small 25.0N tool is placed on the shelf midway between the points where the wires are attached to it.

a) find the tension in the left wire

b) find the tension in the right wire

**2. Homework Equations**

[tex]\Sigma[/tex]Fx = 0 (condition for equilibrium)

[tex]\Sigma[/tex]Fy = 0 (condition for equilibirum)

[tex]\Sigma[/tex][tex]\tau[/tex]z = 0 (condition for equilibirum)

**3. The Attempt at a Solution**

[tex]\Sigma[/tex]Fy = 0 = TL(.25m) + TR(.75m) - (25+49) = 0

[tex]\Sigma[/tex]Fx = 0

tension in the left wire (torque measured from right wire)

[tex]\Sigma[/tex][tex]\tau[/tex]z = 0 =TR(0) + TL(.6) + 25(.2) + 49(.3)

TL = 33N

tension in the right wire (torque measured from left wire)

[tex]\Sigma[/tex][tex]\tau[/tex]z = 0 =TL(0) + TR(.2) + 25(.4) + 49(.3)

TR = 124N

checking with the FY equation I don't think I got the correct tensions, any help is greatly appreciated.