Finding tension in suspended shelf

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SUMMARY

The discussion focuses on calculating the tension in two wires supporting a 50.0 cm shelf with a uniform weight of 60.0 N and an additional 23.0 N tool placed at its midpoint. The left wire tension (TL) was calculated to be 56.5 N, while the right wire tension (TR) was found to be 26.5 N. The calculations utilized the principles of static equilibrium, specifically the sum of torques and forces being equal to zero. Corrections were suggested regarding the placement of weights and the signs used in the equations.

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Homework Statement


A 50.0 cm, uniform, 60.0 N shelf is supported horizontally by two vertical wires attached to the sloping ceiling (the figure (Intro 1 figure) ). A very small 23.0 N tool is placed on the shelf midway between the points where the wires are attached to it.
Find the tension in left wire.
Find the tension in right wire.

Intro figure 1:http://session.masteringphysics.com/problemAsset/1039059/5/YF-11-23.jpg


Homework Equations


[tex]\sum[/tex][tex]\tau[/tex]=0
[tex]\sum[/tex]F=0



The Attempt at a Solution


0 = (23 N)(.15 m)- (60 N)(.225 m) + TL(.30 m)
TL = 56.5 N

0= 56.5N + TR - 23N -60N
TR = 26.5


am I doing something wrong? any help is appreciated!
 
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Hi tcd89! :smile:
tcd89 said:
0 = (23 N)(.15 m)- (60 N)(.225 m) + TL(.30 m)

hmm … where did .225 come from? and your pluses and minuses are wrong. :wink:
 

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