Right & Left Hand Limits of (sinx)^tanx: Indeterminate Form 0^0

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Discussion Overview

The discussion centers on determining the right hand limit (RHL) and left hand limit (LHL) of the expression (sinx)^tanx as x approaches 0, which is identified as an indeterminate form 0^0. Participants explore the behavior of the function near this point and the implications of approaching from either side of zero.

Discussion Character

  • Exploratory
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant asks for clarification on the RHL and LHL of (sinx)^tanx as x approaches 0, acknowledging the indeterminate nature of 0^0.
  • Another participant suggests that as x approaches 0 from the right, the limit approaches 1, while the limit from the left does not exist due to the undefined nature of the function for negative values.
  • A third participant emphasizes the importance of specifying the direction from which x approaches 0, clarifying that the left hand limit involves negative values of x and the right hand limit involves positive values.
  • This participant also notes that the graph indicates the function approaches 1 from the right but cannot approach 0 from the left.

Areas of Agreement / Disagreement

Participants generally agree on the definitions of the right hand and left hand limits, but there is contention regarding the existence of the left hand limit, with differing views on its behavior as x approaches 0 from the left.

Contextual Notes

There are limitations in the discussion regarding the assumptions made about the behavior of the function near zero, particularly concerning the undefined nature of the function for negative values of x.

erisedk
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What is the right hand and left hand limit of (sinx)^tanx?
I know this is an indeterminate form 0^0 but what are the RHL and LHL because though I intuitively know that 0^0 is indeterminate, I don't understand what the right hand and left hand limits are?
 
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As I implement!

$$\lim_{x\rightarrow 0}sinx^{tanx}$$

look at the graph of the function

http://www.wolframalpha.com/input/?i=sin x^{tan x}

And this is intuitively reasonable,
Let us assume a very small value approaching to zero for theta [in radians] , say 0.00000001, then the value will be very close to 1
This is the limit from the right .
And the limit from the lift doesn't exist since you x^x is not always valid for negative numbers..,Hope that is right and what you are looking for ,,
:)
 
Last edited:
It doesn't make sense to talk about "limits" at all without saying what x itself if going to. I presume here you mean "limit as x goes to 0". The "left hand limit" would be as x approaches 0 "from the left" on the number line- that is, x is always negative. The "right hand limit" would be as x approaches 0 "from the right on the number line- x is always positive.

You should be able to see from your graph that if x is approaching 0 "from the right" or "from above", then f(x) goes to 1 while it cannot approach 0 "from the left" or "from below" because, as Maged Saeed said, sin(x)tan(x) is not defined there.
 
Ok thanks :D
 

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