Rigid body kinetics -- force on ankle joint

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Homework Help Overview

The discussion revolves around the application of rigid body kinetics, specifically focusing on the conservation of angular momentum and its implications for calculating forces at the ankle joint during an impact scenario.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the relationship between angular momentum before and after impact, questioning the validity of the equations presented. There is a focus on understanding the implications of angular momentum conservation and the role of impulse in the context of a collision.

Discussion Status

The discussion is active, with participants questioning the assumptions made regarding angular momentum and the axis of rotation. Some participants have provided calculations and are seeking confirmation of their validity, while others are raising concerns about the conservation principles involved.

Contextual Notes

There is a mention of a collision duration of 20 milliseconds, which some participants suggest may be relevant for impulse calculations. Additionally, there is confusion regarding the definitions of terms and the axes involved in the problem setup.

mastermechanic
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Homework Statement
Rigid body kinetics problem involving Impulse-Momentum application
Relevant Equations
G = m.v and H = m.v.r
PROBLEM
H55.PNG


Here from the conservation of angular momentum I found angular velocity just before impact,
$$ H_1 = 0 $$
$$ H_2 = I_0\omega + mV_0d $$
$$ H_2 = 66\omega + 76.(1.2).(0.87)$$
$$ H_1 = H_2 $$
$$ \omega = 1.202 rad/s $$

But I couldn't solve it to find joint force.

Thanks in advance,
 
Last edited:
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mastermechanic said:
$$ H = I_0\omega + mV_0d $$
What is H in this equation? If it is supposed to express angular momentum conservation, the equation does not look like it. Angular momentum conservation is expressed as $$L_{\text{before}}=L_{\text{after}}.$$Is your ##d## the same as ##h## in the figure? How are you going to use the information that the collision lasts 20 msec? Hint: Think "impulse".
 
Last edited:
You're right I just wrote it fast, the angular momentum is zero before the impact and is the expression I wrote above after the impact. So I found $$ \omega = 1.202 rad/s $$

I found a way but I appreciate if you confirm it's validity,

V of the ankle joint,

$$ V = \omega.r $$
$$V = 1.202 * 0.87 = 1.05 m/s $$
$$ \frac {m.(V_f - V_i)} {t} = \frac {76.(1.05 - 1.2)} {0.02} = - 585 N $$

Is this correct?
 
Last edited:
mastermechanic said:
You're right I just wrote it fast, the angular momentum is zero before the impact
The angular momentum about what axis is zero before the impact?
 
jbriggs444 said:
The angular momentum about what axis is zero before the impact?

To the page
 
mastermechanic said:
Is this correct?
It's what I got. Nevertheless, think about the answer you gave to @jbriggs444. If the angular momentum is zero before the impact and non-zero after the impact, it cannot be conserved through the collision, can it?
 
Last edited:
mastermechanic said:
To the page
The page? I do not understand. The page is a plane. An axis is a line. If you draw a normal rising out of the page, that still does not define an axis because no location for the line is defined.

The problem statement gives a large hint about what axis to use. The problem is that you've not correctly used it.
 

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