Rigid body kinetics -- force on ankle joint

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mastermechanic
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Homework Statement
Rigid body kinetics problem involving Impulse-Momentum application
Relevant Equations
G = m.v and H = m.v.r
PROBLEM
H55.PNG


Here from the conservation of angular momentum I found angular velocity just before impact,
$$ H_1 = 0 $$
$$ H_2 = I_0\omega + mV_0d $$
$$ H_2 = 66\omega + 76.(1.2).(0.87)$$
$$ H_1 = H_2 $$
$$ \omega = 1.202 rad/s $$

But I couldn't solve it to find joint force.

Thanks in advance,
 
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mastermechanic said:
$$ H = I_0\omega + mV_0d $$
What is H in this equation? If it is supposed to express angular momentum conservation, the equation does not look like it. Angular momentum conservation is expressed as $$L_{\text{before}}=L_{\text{after}}.$$Is your ##d## the same as ##h## in the figure? How are you going to use the information that the collision lasts 20 msec? Hint: Think "impulse".
 
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You're right I just wrote it fast, the angular momentum is zero before the impact and is the expression I wrote above after the impact. So I found $$ \omega = 1.202 rad/s $$

I found a way but I appreciate if you confirm it's validity,

V of the ankle joint,

$$ V = \omega.r $$
$$V = 1.202 * 0.87 = 1.05 m/s $$
$$ \frac {m.(V_f - V_i)} {t} = \frac {76.(1.05 - 1.2)} {0.02} = - 585 N $$

Is this correct?
 
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jbriggs444 said:
The angular momentum about what axis is zero before the impact?

To the page
 
mastermechanic said:
To the page
The page? I do not understand. The page is a plane. An axis is a line. If you draw a normal rising out of the page, that still does not define an axis because no location for the line is defined.

The problem statement gives a large hint about what axis to use. The problem is that you've not correctly used it.