Rigid Body Mechanics - 2 or more bodies

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SUMMARY

The discussion focuses on deriving the equations of motion for two rigid bodies, one rotating and the other exhibiting a combination of rotation and translation. The term C1, which multiplies the angular velocity squared (ω²), is identified as position-dependent and has units of mass*length², suggesting a relationship to the moment of inertia. The derived equation of motion is ΣM = C1*ω² + Ieq*α, where both C1 and Ieq are functions of position. The author confirms the accuracy of their results by comparing them with outputs from Rigid Body Dynamics solvers Recurdyn and Adams.

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Jason NIcholson
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When I derive the equations of motion for 2 or more bodies where one is rotating and the other is a mixture of rotation and translation, I get a term multiplying angular velocity squared. I know its right but I don't know what to call it. Can some help me with what to call it (it means C12 below)?After eliminating one of the constrained degrees of freedom, I get an ODE for the rotational degree of freedom:
sum of moments = Coefficient1*angularVelocity2+equavelentInertia*angularAcceleration
ΣM = C12 + Ieq

What's interesting about C1 is that it position dependent and it can flip signs. C1 has units of mass*length2 thus the units are consistent since ω has units of radians/sec.
 
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A priori, this looks like a term for rotational kinetic energy, with C1 related to the moment of inertia. I don't see why it is position dependent,. You should probably give some details of the derivation if you want to get help with this.
 
The video below shows the motion.


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thickness = 2*10mm = 20mm. member is extruded 10mm each way.
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thickness = 2*5mm = 10 mm. member is extruded 5mm each way.
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member1 rotates around the z axis. member2 is constrained at one end to move vertically at distance of 80mm from the YZ plane. The two body are constrained to each other via a revolute joint. Solving the equations motion for one ODE in terms of the rotational displacement, velocity, and acceleration of member1 yields an equation that looks like:

$$\sum M = C_1(\beta')^2 + I_eq\beta''$$

##\beta## is the rotational position of member1. Both ##C_1## and ##I_{eq}## are a functions of position.

I am not convinced it is rotational energy. I have compared my results against Rigid Body Dynamics solver Recurdyn and Adams. I can match their answers so I am confident I have got the equations of motion correct.
 

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