- #1

wjdgone

## Homework Statement

Imagine you have two RLC circuits you are trying to scan for resonances. They have identical resonant frequencies, but circuit 1 has a very high Q-factor

(Q1 >> 1), and circuit 2 has a very low Q-factor (Q2 < 1). Let's assume you are already

on resonance and looking at V(out) on the oscilloscope, and you change the frequency in either direction for both circuits. How will the amplitude response differ between circuits 1

and 2 as you move the driving frequency away from resonance?

## Homework Equations

Q=R/(2*pi*f*L) - not sure if I need this in the first place

## The Attempt at a Solution

I don't think I understand what the problem means by "as you move the driving frequency away from resonance." My best blind stab in the dark for this problem is that Q1 means that R>2*pi*f*L and Q2 means that R<2*pi*f*L, and I can relate the inductance to the change in amplitude such that if inductance decreases, amplitude increases? (I'm also not sure how to relate inductance to amplitude.)