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## Homework Statement

A 10 μF capacitor and a 25 H inductor are connected in series with a 60 Hz source whose rms output is 112 V.

Find the voltage drop across the inductor. Answer in units of V.

Note: Sigfigs do not matter

## Homework Equations

I = V/Z where Z is the impedence

XL = omega*L

XC = 1/omega*C

## The Attempt at a Solution

I assumed the closed circuit was connected thus: battery to the capacitor, the capacitor to the inductor, the inductor to the battery.

I found the current using equation I = V/Z (the answer was correct)

I found the voltage drop across the capacitor by the equation V - I*XL = [tex]\Delta[/tex]V (the answer was correct)

For the voltage drop across the inductor I tried I*XC - V. The answer is incorrect.

Could anyone tell me what I'm doing wrong?

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