A 10 μF capacitor and a 25 H inductor are connected in series with a 60 Hz source whose rms output is 112 V.
Find the voltage drop across the inductor. Answer in units of V.
Note: Sigfigs do not matter
I = V/Z where Z is the impedence
XL = omega*L
XC = 1/omega*C
The Attempt at a Solution
I assumed the closed circuit was connected thus: battery to the capacitor, the capacitor to the inductor, the inductor to the battery.
I found the current using equation I = V/Z (the answer was correct)
I found the voltage drop across the capacitor by the equation V - I*XL = [tex]\Delta[/tex]V (the answer was correct)
For the voltage drop across the inductor I tried I*XC - V. The answer is incorrect.
Could anyone tell me what I'm doing wrong?