# Homework Help: Rocket Equation and Orbit questions?

1. Dec 16, 2012

### picklepie159

1. The problem statement, all variables and given/known data
#1.) A rocket exhausts fuel with a velocity of 1500 m/s, relative to the rocket. It starts from outer space with fuel comprising 80 per cent of the total mass. When all the fuel has been exhausted the speed is...

2. Relevant equations

Vrel (dm/dt) = m (dv/dt)

(Does conservation of momentum apply here? I know it applied to an earlier problem, but the velocity of the ejected gasses weren't relative to the rocket)

3. The attempt at a solution

1500 (0.8) = 0.2 v
v = 600 m/s

1500 (0.8) = 1 v
v = 1200... still wrong.

Can anyone help me out here??

Also, if a man in a circular orbit around earth fires his forward thrusters to drop his KE, would he fall into a larger elliptical orbit with a greater period? It was a question in the book I was confused about.
I know K = -E and E = - GMm/2r , or - GMm/2a

2. Dec 16, 2012

### haruspex

Yes, you need to use conservation of momentum, but the mass of the rocket is changing, so you need it in the form of a differential equation. The equation you quoted is fine, but you don't really care about time here. Can you rewrite it without using dt?

3. Dec 16, 2012

### picklepie159

I understand it's not okay to treat the dt's as a part of a fraction, but I'm learning calc alongside with physics and this is the only thing I could think of. It's not correct, but I would love to learn how to rewrite it as you suggested.

Vrel * dm = m * dv
1500 * 0.8 = dv

4. Dec 16, 2012

### haruspex

Yes
No, dm is a small change in mass. You need to rearrange and integrate the eqn.

5. Dec 16, 2012

### picklepie159

dv/dm = Vrel/m

v = Vrel * ln(m)

2414 = -1500 * ln(0.2).

Awesome, thanks a lot!