What Is the Velocity of a Leaking Bucket at the Moment It Empties?

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SUMMARY

The discussion focuses on calculating the velocity of a leaking bucket at the moment it empties, using the rocket equation: Fext = m dv/dt - Vrel dm/dt. The total mass of the bucket and water is expressed as M' = M + m - mt/T, where M is the mass of the empty bucket, m is the initial mass of the water, and T is the time taken to empty. A key point is the concept of relative velocity, where the leaking water has zero velocity relative to the bucket at the instant of emptying, despite the bucket's acceleration.

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  • Basic knowledge of relative velocity concepts
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Homework Statement


A bucket of mass M (when empty) initial at rest and containing a mass of water is being pulled up a well by a rope exerting a steady force P. The water is leaking out of the bucket at a steady rate such that the bucket is empty after a time T. Find the velocity of the bucket at the instant it becomes empty.


Homework Equations


rocket equation:
Fext = m dv/dt - Vrel dm/dt

The Attempt at a Solution


the total mass of the bucket and water is M' = M + m - mt/T , where m is the initial mass of the water.
The hint said " as the leaking water has zero velocity relative to the bucket.."

I don't understand it. Why Water should have zero velocity relative to the bucket?? Water is leaking out at a steady rate, so there should be a non-zero constant velocity. i am so confused.
 
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It is just like a aircraft drop a bomb when it flies. The bomb will move with the same speed as the aircraft.

The relative velocity of water relative to the bucket is 0, however in this question,the bucket is accelerating so the zero relative velocity only last for an instant.
 

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