Rocket Escape Velocity from the Earth-Sun system

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SUMMARY

The discussion focuses on calculating the rocket's escape velocity from the Earth-Sun system, emphasizing the importance of gravitational potential energy. It establishes that the rocket is freed from Earth's gravity at an infinite distance from Earth, but this distance becomes negligible when measured from the Sun due to the Sun's dominant mass. The conversation highlights the additive nature of gravitational potential energy, allowing for calculations to be performed in two steps: one for Earth and one for the Sun. Additionally, it notes that the rocket escapes from both gravitational influences simultaneously, factoring in the Earth's motion relative to the Sun.

PREREQUISITES
  • Understanding of gravitational potential energy
  • Familiarity with escape velocity concepts
  • Basic knowledge of celestial mechanics
  • Proficiency in energy conservation equations
NEXT STEPS
  • Study gravitational potential energy calculations in multi-body systems
  • Learn about escape velocity from different celestial bodies
  • Explore the effects of relative motion in gravitational fields
  • Investigate energy conservation principles in astrophysics
USEFUL FOR

Astronomy students, aerospace engineers, physicists, and anyone interested in understanding the dynamics of rocket propulsion in multi-body gravitational fields.

Rikudo
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Homework Statement
Earth with mass m orbits the sun (mass M) in circular path (radius R) with velocity v. If a rocket is launched from the earth,find the initial velocity that is needed so that it could leave the solar system (free from both the sun's and earth's gravity).

Note-
this process undergoes two independent steps: free from the earth's gravity, and then free from the sun's gravity.
Relevant Equations
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I have a difficulty when making the energy-conservation-equation for the second step.

When making the equation, we need to know the exact position (measured from the sun) of the rocket after it is freed from the Earth gravitation.

But, where exactly does the rocket free from Earth gravitation? All I know is that this happens at infinity (measured from the earth).

Does this "infinity" negligible if we measure it from the sun? Why?
 
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The Earth's mass is much smaller than the Sun, so you could approximate a long way from Earth as still a distance ##R## from the Sun.
 
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Alternately, one could realize that gravitational potential energy is additive. If you add the gravitational potential energy of the rocket in the field of the Earth to the gravitational potential energy of the rocket in the field of the Sun the result is the gravitational potential energy of the rocket in the field of the Sun and Earth combined.

So you can do the calculations in two separate steps and add the results together. But there is no need to do the physical thrusting in two distinct steps. You are actually escaping from both bodies at the same time.
 
In addition to what has already been mentioned regarding adding two speed delta's being a reasonable approximation, you should also remember to consider that the Earth already moves relative to the Sun.
 

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