Rocket Escape Velocity from the Earth-Sun system

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Homework Help Overview

The discussion revolves around calculating the escape velocity of a rocket from the Earth-Sun system, focusing on the energy conservation equation and the position of the rocket after leaving Earth's gravitational influence.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants explore the concept of gravitational influence and the definition of "infinity" in the context of the Earth and Sun. Questions are raised about the significance of the rocket's position relative to the Sun once it is freed from Earth's gravity. Some suggest that gravitational potential energy can be treated additively, while others discuss the implications of the Earth's motion relative to the Sun.

Discussion Status

The discussion is active with various interpretations being explored. Some participants offer insights into the additive nature of gravitational potential energy and the relative motion of the Earth and Sun, indicating a productive exchange of ideas without reaching a consensus.

Contextual Notes

There is an ongoing examination of the assumptions regarding the distances involved and the simplifications that can be made in the calculations, particularly concerning the relative masses of the Earth and Sun.

Rikudo
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Homework Statement
Earth with mass m orbits the sun (mass M) in circular path (radius R) with velocity v. If a rocket is launched from the earth,find the initial velocity that is needed so that it could leave the solar system (free from both the sun's and earth's gravity).

Note-
this process undergoes two independent steps: free from the earth's gravity, and then free from the sun's gravity.
Relevant Equations
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I have a difficulty when making the energy-conservation-equation for the second step.

When making the equation, we need to know the exact position (measured from the sun) of the rocket after it is freed from the Earth gravitation.

But, where exactly does the rocket free from Earth gravitation? All I know is that this happens at infinity (measured from the earth).

Does this "infinity" negligible if we measure it from the sun? Why?
 
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The Earth's mass is much smaller than the Sun, so you could approximate a long way from Earth as still a distance ##R## from the Sun.
 
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Alternately, one could realize that gravitational potential energy is additive. If you add the gravitational potential energy of the rocket in the field of the Earth to the gravitational potential energy of the rocket in the field of the Sun the result is the gravitational potential energy of the rocket in the field of the Sun and Earth combined.

So you can do the calculations in two separate steps and add the results together. But there is no need to do the physical thrusting in two distinct steps. You are actually escaping from both bodies at the same time.
 
In addition to what has already been mentioned regarding adding two speed delta's being a reasonable approximation, you should also remember to consider that the Earth already moves relative to the Sun.
 

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