Rocket fuel consumption too easy?

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SUMMARY

The discussion focuses on the calculation of rocket fuel consumption using a linear equation derived from the mass flow rate. The equation presented is m(t) = [(m(final) - m(initial)) / t(final)]t + m(initial), which describes the mass of the rocket as a function of time, assuming a constant rate of fuel consumption. Participants confirm that this approach is valid under the condition of constant mass loss, aligning with principles of linear equations.

PREREQUISITES
  • Understanding of linear equations and graph slopes
  • Basic knowledge of rocket physics and mass flow rate
  • Familiarity with time intervals in physics problems
  • Concept of derivatives and integrals in calculus
NEXT STEPS
  • Study the principles of rocket propulsion and fuel consumption dynamics
  • Learn about the application of derivatives in physics, particularly in motion equations
  • Explore advanced topics in calculus related to mass flow and variable rates
  • Investigate the implications of non-constant mass loss in rocket equations
USEFUL FOR

Students studying physics, particularly those focusing on rocket science and dynamics, as well as educators looking for examples of mass flow rate calculations in practical applications.

shutoutsteve
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Homework Statement


Rocket with fuel mass of m(initial)
Rocket without fuel is m(final)
Time for fuel to be used up is t(final)


Homework Equations


What is m(t) (slope of m vs t graph)
(i assume t(initial) is zero

The Attempt at a Solution



[((m(final) -m(initial)) / t(final)]t + m(initial) for interval 0<t<tf

just mx+b?
 
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shutoutsteve said:

Homework Statement


Rocket with fuel mass of m(initial)
Rocket without fuel is m(final)
Time for fuel to be used up is t(final)


Homework Equations


What is m(t) (slope of m vs t graph)
(i assume t(initial) is zero

The Attempt at a Solution



[((m(final) -m(initial)) / t(final)]t + m(initial) for interval 0<t<tf

just mx+b?

That's true if mass is lost at a constant rate.
 
Yes, that was given too.
Our other assignment page is covered in derivatives and integrals, but my answer for this one was simple math, so I was worried I had it wrong. :)
 

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