Rocket Problem: Determining the amount of fuel burned

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Homework Help Overview

The discussion revolves around a physics problem involving a rocket's acceleration and fuel consumption. The context includes a 20,000 kg rocket with a thrust of 3x10^5 N, focusing on calculating initial acceleration and the mass of fuel burned at a specific altitude.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the initial acceleration calculation and question the relevance of altitude in determining fuel burned. There is an exploration of how thrust and mass affect acceleration.

Discussion Status

Some participants have provided insights into the relationship between thrust, mass, and acceleration. There is an acknowledgment of the changing mass of the rocket as fuel is burned, which may lead to further calculations.

Contextual Notes

Participants are considering the implications of the rocket's altitude on the problem, with some suggesting it may not be necessary for the calculations at hand.

Ockham
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The set up:
A 20,000kg rocket has a motor that generates a thrust of 3x10^5 N.


The problem:
a)What is it's initial Acceleration?

b)At an altitude of 5,000m the rockets acceleration has increased to 6 m/s^2, what mass of fuel has it burned?

Relevant equations:

F = ma

The attempt at a solution:

I found the initial Acceleration to be 5.2 by taking the difference of the thrust and the rockets weight and dividing my the initial mass.

Part two is the one I can't figure out...I don't think the height of the rocket has anything to do with the solution does it?
 
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I agree, the altitude is unnecessary. In fact, it's a bit odd because you could calculate the altitude, and I'll bet it's not 5km exactly.
 
How do I determine the amount of fuel burned?
 
Recall how you calculated the initial acceleration. Why does the acceleration increase? What, in your calculation, will have remained constant?
 
OH...thanks. I get it now. The Thrust is constant the only thing that changes is the mass. Which I can solve for.


Thank you!
Ockham
 

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