Rocket trajectory in vertical launch then free fall

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SUMMARY

The discussion focuses on calculating the total height achieved by a rocket launched vertically at a constant velocity of 20 m/s for 35 seconds before its fuel supply is cut off. The initial displacement is calculated as 700 meters using the formula displacement = velocity * time. However, the discussion emphasizes that this calculation does not account for the additional height gained during free fall until the rocket's velocity reaches 0 m/s, which must be included for an accurate total height assessment.

PREREQUISITES
  • Understanding of kinematic equations
  • Basic knowledge of free fall physics
  • Familiarity with velocity and displacement concepts
  • Ability to perform calculations involving time and acceleration
NEXT STEPS
  • Study the kinematic equations for uniformly accelerated motion
  • Learn about the effects of gravity on free-falling objects
  • Explore the concept of maximum height in projectile motion
  • Investigate the relationship between velocity, time, and displacement in free fall
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Students studying physics, educators teaching kinematics, and anyone interested in understanding the dynamics of rocket launches and free fall motion.

jontyjashan
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Homework Statement


A rocket is launched to travel vertically upward with a constant velocity of say...20 m/s.After
travelling maybe 35 s the rocket develops snag and its fuel supply is cut off. the rocket then travels like a free body, the height achieved by the rocket will be



Homework Equations


displacement=velocity *time

The Attempt at a Solution


20 *35=700m

this is not the answer why?
 
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you add to that the extra displacement the rocket travels as a free body till the point where its velocity reachs [0 m/s]
 

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