Rock's Max Horizontal Distance from Volcano: 500m

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Homework Help Overview

The problem involves a volcano that ejects rocks at a certain speed and height, and the goal is to determine the maximum horizontal distance the rocks can travel. The subject area includes kinematics and projectile motion.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the initial conditions of the problem, including the speed of the rocks and the height of the volcano. There are attempts to apply relevant equations for projectile motion, and questions arise regarding the direction of the rocks' motion and the appropriate equations to use.

Discussion Status

The discussion is ongoing, with some participants providing guidance on how to incorporate the height of the volcano into the calculations. Multiple interpretations of the problem are being explored, and there is no explicit consensus yet.

Contextual Notes

Participants note the importance of considering the height of the volcano in their calculations, which has not been adequately addressed in initial attempts.

peace1709
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A 500m high volcano eject rocks at a speed 30 m/s.What is max horizontal distance reached by the rock?
 
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Hi peace1709, Welcome to PF.
What do you about the problem?
In what direction the rocks are moving?
which are the relevant equations?
 
i use the equation range= [(V initial)^2 x (sin 2A)]/[g].
where v inital is 30 m/s and i assume A=45 degrees, and g=9.8 m/s^2
but i got the answer wrong.
 
i got 91.7 m and its wrong, can u help me?
 
In your calculation you have not taken into account the height of the volcano.
 
oh ya.but i don't know how to relate the height. can u help me?
 
You can use the formula
y = yo + v*t - 0.5*g*t^2.
Here v = vo*sinθ
And t = x/vo*cosθ
y is the final position of the rock and yo is the initial position of the rock.
 

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