Roll 2 fair dice, find pdf and cdf

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SUMMARY

This discussion focuses on calculating the probability density function (pdf) and cumulative distribution function (cdf) for the random variable defined by rolling two fair dice. The random variable X is defined as X = {i+j if i+j ≤ 6; abs.value(i-j) otherwise}. The provided solutions indicate that the pdf is f(x) = {3/36 if x=0; 5/36 if x=2, 4, or 6; 6/36 if x=1, 3, or 5} and the cdf is f(x) = {0 if x<0; 3/36 if 0≤x<1; 9/36 if 1≤x<2; 14/36 if 2≤x<3; 20/36 if 3≤x<4; 25/36 if 4≤x<5; 31/36 if 5≤x<6; 1 if x≥6}. The key to solving the problem involves calculating the probabilities for each outcome pair (i,j) and determining the corresponding values of X.

PREREQUISITES
  • Understanding of probability theory, specifically discrete random variables.
  • Familiarity with the concept of probability density functions (pdf) and cumulative distribution functions (cdf).
  • Basic knowledge of rolling dice and combinatorial outcomes.
  • Ability to perform calculations involving absolute values and inequalities.
NEXT STEPS
  • Study the derivation of probability density functions for discrete random variables.
  • Learn how to compute cumulative distribution functions from probability density functions.
  • Explore examples of random variables defined by multiple conditions, similar to the defined variable X.
  • Practice problems involving rolling dice and calculating probabilities for various outcomes.
USEFUL FOR

Students preparing for statistics or probability exams, educators teaching probability concepts, and anyone interested in understanding the statistical properties of random variables derived from dice rolls.

srk827
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Hi guys. I have a test tomorrow and I am trying to work out the problems on the review sheet, but I can't figure out this one dealing with pdf and cdf.

Roll 2 fair dice and call each outcome (i,j) where i,j = 1,2,...6.
Define: X= {i+j if i+j ≤ 6 ; abs.value(i-j) otherwise}

A) Find and draw the pdf.
B) Find and draw the cdf.



The professor sent us the solutions. I just can't figure out how he got it. The solution he sent was:

a)
f(x)= { 3/36 if x=o; 5/36 if x=2 or 4 or 6; 6/36 if x=1 or 3 or 5}

b) f(x)= {0 if x<0; 3/36 if 0≤x<1; 9/36 if 1≤x<2; 14/36 if 2≤x<3; 20/36 if 3≤x<4; 25/36 if 4≤x<5; 31/36 if 5≤x<6; 1 if x≥6}

Could someone please help me understand the steps to take to get this answer?
 
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srk827 said:
Hi guys. I have a test tomorrow and I am trying to work out the problems on the review sheet, but I can't figure out this one dealing with pdf and cdf.

Roll 2 fair dice and call each outcome (i,j) where i,j = 1,2,...6.
Define: X= {i+j if i+j ≤ 6 ; abs.value(i-j) otherwise}

A) Find and draw the pdf.
B) Find and draw the cdf.



The professor sent us the solutions. I just can't figure out how he got it. The solution he sent was:

a)
f(x)= { 3/36 if x=o; 5/36 if x=2 or 4 or 6; 6/36 if x=1 or 3 or 5}

b) f(x)= {0 if x<0; 3/36 if 0≤x<1; 9/36 if 1≤x<2; 14/36 if 2≤x<3; 20/36 if 3≤x<4; 25/36 if 4≤x<5; 31/36 if 5≤x<6; 1 if x≥6}

Could someone please help me understand the steps to take to get this answer?

First find the probabilities of all the individual pairs (i,j). For each pair (i,j), figure out what x must be. Of course, the same x might be obtained for several different pairs (i,j), so you need to be careful. That's it; that's all there is to it.

RGV
 

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