A mass of 100kg is h meters high on a track that extends into a loop that has a radius of 20m. Assume track is frictionless. I need to find minimum height for the mass to make it around the loop without falling off or going backwards.
Conservation of Energy:
The Attempt at a Solution
This may be right, i only need someone to check my work in case im incorrect. So, from K_1+U_1=K_2+U_2 i get K=U
From there i have 1/2mv^2=mgh
masses cancel so v^2=2gh
from there i find centripetal force = (mv^2)/r=F
masses again cancel so i find that g=(v^2)/r
I replace v^2 with 2gh so i find that g=2gh/r
g's cancel so i find that h=r/2 plug in for r: h = 20/2=10meters.
Can someone verify that im correct? thanks in advance!