Roller Coaster Problem with Friction

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SUMMARY

The roller coaster problem involves calculating the speed at point B given the initial speed at point A, the heights at points A, B, and C, and the force of friction. The average force of friction is one sixth of the weight of the roller coaster. The correct final speed at point B is determined to be 24 m/s after correcting the change in height in the calculations. The initial attempt yielded an incorrect speed of 23.5 m/s due to an error in height difference.

PREREQUISITES
  • Understanding of basic physics concepts such as energy conservation and forces.
  • Familiarity with the equations of motion and work-energy principle.
  • Knowledge of gravitational acceleration (9.8 m/s²) and its application in problems involving height.
  • Ability to perform algebraic manipulations to solve for unknown variables in equations.
NEXT STEPS
  • Review the work-energy principle in physics to solidify understanding of energy transformations.
  • Practice problems involving friction and roller coaster dynamics to enhance problem-solving skills.
  • Explore the effects of varying friction coefficients on roller coaster speeds and safety.
  • Learn about the role of gravitational potential energy in mechanical systems.
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of roller coasters and the impact of friction on motion.

Bones
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Homework Statement


Suppose the roller coaster in the figure (h1 = 35 m, h2 = 13 m, h3 = 20) passes point A with a speed of 2.70 m/s. If the average force of friction is equal to one sixth of its weight, with what speed will it reach point B? The distance traveled is 35.0 m.
http://www.webassign.net/gianpse3/8-29alt.gif

Homework Equations


Work force of friction = [1/2mv2^2-1/2mv1^2] + [mgh2-mgh1]

The Attempt at a Solution


I took 1/6(9.8m/s^2)(35m) = [1/2v2^2-1/2(2.7m/s)^2] + [(9.8m/s^2)(13m)-(9.8m/s^2)(35m)] and got 23.5m/s which is not correct...what am I doing wrong?
 
Last edited:
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Please help I am really frustrated with this one!
 
I figured it out, I had the change in height incorrect. V^2 = 2(9.8m/s^2)(35m) + (2.7m/s)^2 - 1/6(9.8m/s^2)(35m)
V=24m/s
 

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