K.E (rotational) = .5*I*omega^2
K.E (translational) = .5*m*v^2
The Attempt at a Solution
v(of rod and translational vel of cylinder) = L * (dαlpha/dt)
Is the angular velocity of the cylinder the same as the angular velocity of the rod?
To calculate the translational K.E of the cylinder can I use the vel I've calculated above for the rod?
For the rotational vel of the cylinder, can i use I (com) = 0.5*m*r^2