Rope tension no friction question

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SUMMARY

The discussion centers on calculating the tension in a rope used to accelerate a 1050 kg car horizontally at 1.20 m/s², while ignoring friction. The initial approach incorrectly included gravitational force in the tension calculation. The correct application of Newton's second law requires focusing solely on horizontal acceleration, leading to the conclusion that the tension should be 1.26 x 10³ N. The mistake was clarified through the suggestion to draw a free-body diagram and apply Newton's second law separately for both the x and y directions.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Ability to draw and interpret free-body diagrams
  • Basic knowledge of forces and acceleration
  • Familiarity with unit conversions in physics
NEXT STEPS
  • Study the application of Newton's second law in various scenarios
  • Learn how to effectively draw and analyze free-body diagrams
  • Explore the concept of tension in different contexts, such as pulleys and inclined planes
  • Review problems involving horizontal acceleration and frictionless surfaces
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of forces and motion, particularly in scenarios involving tension and acceleration without friction.

PearlyD
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Homework Statement


How much tension must a rope withstand if it is used to accelerate a 1050kg car horizontally at 1.20 m/s2? IGNORE FRICTION!



The Attempt at a Solution


What i did was
T-Fg=ma
T-mg=ma
T-1050(9.8)=1050(1.20)
T-10290=1260
T=1.15x10 to the power of 4
But that's not the answer the answer is 1.26x to the power of 3kg
What did i do wrong?
 
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Why are you including gravity? It's not as if you're lifting the car up.

Try drawing a free-body diagram and writing out Newton's second law TWICE, once for the y direction and once for the x direction.
 
ideasrule said:
Why are you including gravity? It's not as if you're lifting the car up.

Try drawing a free-body diagram and writing out Newton's second law TWICE, once for the y direction and once for the x direction.

Sorry i made a dumb mistake!
its been a long day and i was for some reason including gravity in a lot of things that i shouldn't
i got the question now.
thanks for replying anyways:)
 

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